Thursday, March 9, 2023

Understanding PC and Troubleshooting MCQ - CPU

1. Control BUS is used to control and coordinate the CPU Operations.



2. Protected Mode is used in multi-tasking machines. 



3.Control BUS is also called as Timing and control BUS.




4. RISC chips have faster CPU performance than CISC. (True or False) 




5. Multiprocessing  is a technique of running more than one process in a system. 




6. MMX is an extension that supports Multimedia applications.




7. 8088 use  8  bit BUS while the 8086 uses 16 bit BUS for data transfer.



8. The speed specification of clock multiplier of the 8088/86 processor is 1.0 . 




9. The motherboard interface of 8088/86 packaging is DIP socket . 




10. The two types of Intel 386 are DS & SX . 




11. State whether the following statements are true or false.

        a. Pentium is the first superscalar processor. TRUE
        b. The use of speculative executive will not reduce pipeline stall time in the RISC core in                 sixth generation processor. - FALSE


 12.Which are the three major steps in overclocking? 

       Change in BUS speed, Change the multiplier, Change the voltage supply. 




13. Overclocking the Intel Celeron depends on Motherboard Characteristics . 




14. FSB Stands for Front Side BUS .


Wednesday, March 8, 2023

Five persons are selected from a group of 8 men, 6 women and 6 children. Find the probability that 3 of the 5 persons selected are children.

 To find the probability that 3 of the 5 persons selected are children, we need to determine the total number of ways of selecting 5 people from the group of 8 men, 6 women, and 6 children and the number of ways of selecting 3 children from the 6 children.

The total number of ways of selecting 5 people from a group of 20 people is given by the combination formula:

C(20,5) = 20! / (5! * 15!) = 15504

The number of ways of selecting 3 children from a group of 6 children is given by the combination formula:

C(6,3) = 6! / (3! * 3!) = 20

The number of ways of selecting the remaining 2 people from the group of 14 adults (8 men and 6 women) is given by the combination formula:

C(14,2) = 14! / (2! * 12!) = 91

Therefore, the total number of ways of selecting 5 people with 3 children is:

20 * 91 = 1820

The probability of selecting 3 children from a group of 5 people is:

1820 / 15504 ≈ 0.1175

So, the probability that 3 of the 5 persons selected are children is approximately 0.1175 or 11.75%.

Draw the truth tables of Conjunction, disjunction and Biconditional statements.

Here are the truth tables for conjunction, disjunction, and biconditional statements:

Conjunction (AND):

PQP AND Q
TTT
TFF
FTF
FFF

Disjunction (OR):

PQP OR Q
TTT
TFT
FTT
FFF

Biconditional (IF AND ONLY IF):

PQP IF AND ONLY IF Q
TTT
TFF
FTF
FFT

Note: In the biconditional statement, the truth value is only true if both P and Q have the same truth value.